x^2+(x-3)(x+3)=65

Solution for x^2+(x-3)(x+3)=65 equation:

Simplifying
x2 + (x + -3)(x + 3) = 65

Reorder the terms:
x2 + (-3 + x)(x + 3) = 65

Reorder the terms:
x2 + (-3 + x)(3 + x) = 65

Multiply (-3 + x) * (3 + x)
x2 + (-3(3 + x) + x(3 + x)) = 65
x2 + ((3 * -3 + x * -3) + x(3 + x)) = 65
x2 + ((-9 + -3x) + x(3 + x)) = 65
x2 + (-9 + -3x + (3 * x + x * x)) = 65
x2 + (-9 + -3x + (3x + x2)) = 65

Combine like terms: -3x + 3x = 0
x2 + (-9 + 0 + x2) = 65
x2 + (-9 + x2) = 65

Reorder the terms:
-9 + x2 + x2 = 65

Combine like terms: x2 + x2 = 2x2
-9 + 2x2 = 65

Solving
-9 + 2x2 = 65

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 2x2 = 65 + 9

Combine like terms: -9 + 9 = 0
0 + 2x2 = 65 + 9
2x2 = 65 + 9

Combine like terms: 65 + 9 = 74
2x2 = 74

Divide each side by '2'.
x2 = 37

Simplifying
x2 = 37

Take the square root of each side:
x = {-6.08276253, 6.08276253}